Solved f(x)=x2-36x+6A. a=5B. a=-36C. a=6D. a=-6
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If f(x) = (x^2-36)/(x+6) is continuous at x = -6, find f(-6) a)-12 b)12 c)6 d)-6
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Solved f(x)=x2-36x+6A. a=5B. a=-36C. a=6D. a=-6
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Find the domain of f(x) = (x^(2)-36)/(x+6)
curves ( y = f ( x ) , x - a x r s , y ) Write the area of the region bounded by the region enclosed by the curves ( ( x - 6 ) ^ { 2 } + y ^ { 2 } = 36 ) and ( x ^ { 2 } + y ^ { 2 } = 36.24 pi - 18 sqrt { 3 } )
Solved Let f(x)=x2-36 Let f(x) = -x-6. (a) Calculate f(x)
Solved Consider the function f(x) = x3 + 6x2 – 36x + 4 .
Solved f(x) = x-6/x^2-36 g(x) = 3x/x-3 a(x) =x-2 State the
Find the intervals in which the f(x) = 2x3 - 15x2 + 36x + 17 is increasing or decreasing 17. Find the point on the curve y2 = 2x which is a minimum distance from the point (1.4)
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