Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Draw line BC = 11 cm. Make an angle of 30° at B and 90° at C using a protractor. Bisect angles B and C, and these bisectors will meet at one-point X. Now draw perpendicular bisectors on BX and CX, which will cut the line segment BC on point Y and Z respectively. Now join XY and XZ to get the required triangle XYZ.
It is given that we have to construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. We have drawn the triangle using a compass and ruler and justified the construction.

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Construct a ∆XYZ in which angle Y = 30°, angle Z = 90° and XY+ YZ+ZX= 11 cm.​

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Construct a triangle XYZ in which $\angle Y={{30}^{\circ }}$,$\angle Z={{ 90}^{\circ }}$and $XY+YZ+ZX=11$cm \[\]

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